Advertisements
Advertisements
प्रश्न
Evaluate: `(5 sin^2 45^circ - 3 tan^2 30^circ)/(2 sec^2 30^circ)`
Advertisements
उत्तर
1. Identify trigonometric values
First, we recall the standard values for the trigonometric functions involved:
`sin 45^circ = 1/sqrt(2)`
`tan 30^circ = 1/sqrt(3)`
`sec 30^circ = 1/(cos 30^circ)`
= `1/(sqrt(3)/2)`
= `2/sqrt(3)`
2. Substitute and square values
Now, substitute these values into the expression and calculate the squares:
`sin^2 45^circ = (1/sqrt(2))^2`
= `1/2`
`tan^2 30^circ = (1/sqrt(3))^2`
= `1/3`
`sec^2 30^circ = (2/sqrt(3))^2`
= `4/3`
3. Simplify the numerator
Substitute the squared values into the numerator:
Numerator = `5(1/2) - 3(1/3)`
Numerator = `5/2 - 1`
= `(5 - 2)/2`
= `3/2`
Substitute the squared value into the denominator:
Denomiantor = `2(4/3)`
= `8/3`
5. Calculate the final result
Divide the simplified numerator by the simplified denominator:
Expression = `(3/2)/(8/3)`
To divide fractions, multiply by the reciprocal:
Expression = `3/2 xx 3/8`
= `9/16`
