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Evaluate : ∫-111a2ex+b2e-x⋅dx - Mathematics and Statistics

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प्रश्न

Evaluate : `int_(-1)^1 (1)/(a^2e^x + b^2e^(-x))*dx`

योग
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उत्तर

Let I = `int_(-1)^1 e^x/(a^2(e^x)^2 + b^2)*dx`
Put ex = t
∴ ex·dx = dt
When x = 1, t = e
When x = – 1, t = e–1 = `(1)/e`

∴ I = `int_(1/e)^e dt/(a^2t^2 + b^2)`

= `int_(1/e)^e dt/((at)^2 + b^2)`

= `[1/a*1/b tan^-1 ("at"/b)]_(1/e)^e`

= `(1)/"ab" tan^-1 ("ae"/b) - (1)/"ab" tan^-1 (a/"be")`

= `(1)"ab"[tan^-1 ("ae"/b) - tan^-1 (a/"be")]`.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Definite Integration - Exercise 4.2 [पृष्ठ १७२]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 4 Definite Integration
Exercise 4.2 | Q 2.08 | पृष्ठ १७२
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