हिंदी

Eeeed∫e7logx-e6logxe5logx-e4logxdx = ______.

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प्रश्न

`int ("e"^(7logx) - "e"^(6logx))/("e"^(5logx) - "e"^(4logx)) "d"x` = ______.

विकल्प

  • `x^3/3 + "c"`

  • `1/x + "c"`

  • `x^3log x + "c"`

  • `3/x^3 + "c"`

MCQ
रिक्त स्थान भरें
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उत्तर

`int ("e"^(lox) - "e"^(6logx))/("e"^(5logx) - "e"^(4logx)) "d"x` = `x^3/3 + "c"`.

Explanation:

`int ("e"^(7logx) - "e"^(6logx))/("e"^(5logx) - "e"^(4logx)) "d"x = int (x^7 - x^6)/(x^5 - x^4) "d"x`

= `int (x^6(x - 1))/(x^4(x - 1)) "d"x`

= `int x^2 "d"x`

= `x^3/3 + "c"`

shaalaa.com
Algebra of Integration and Standard Results
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