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Edd(e-2xx-yx)dxdy=1(x≠0) when written in the form dydxPdydx+Py = Q, then P = ______. - Mathematics

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प्रश्न

`("e"^(-2sqrt(x))/sqrt(x) - y/sqrt(x))("d"x)/("d"y) = 1(x ≠ 0)` when written in the form `"dy"/"dx" + "P"y` = Q, then P = ______.

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उत्तर

`("e"^(-2sqrt(x))/sqrt(x) - y/sqrt(x))("d"x)/("d"y) = 1(x ≠ 0)` when written in the form `"dy"/"dx" + "P"y` = Q, then P = `1/sqrt(x)`.

Explanation:

`1/sqrt(x)`; the given equation can be written as

`"dy"/"dx" = ("e"^(-2sqrt(x)))/sqrt(x) - y/sqrt(x)`

i.e. `"dy"/"dx" + y/sqrt(x) = ("e"^(-2sqrt(x)))/sqrt(x)`

This is a differential equation of the type `"dy"/"dx" + "P"y` = Q.

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अध्याय 9: Differential Equations - Solved Examples [पृष्ठ १९०]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 9 Differential Equations
Solved Examples | Q 22. (x) | पृष्ठ १९०

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