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प्रश्न
E and F are points on the sides PQ and PR, respectively, of a ΔPQR. For the following case, state whether EF || QR.
PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm and FR = 2.4 cm
योग
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उत्तर
Given that PE = 3.9 cm,
EQ = 3 cm,
PF = 3.6 cm,
FR = 2.4 cm
`("PE")/("EQ")=(3.9)/3`
`39/30 = 13/10`
`("PF")/("FR") = 3.6/2.4 `
`13/10 != 3.6/2.4 `
Hence, `("PE")/("EQ") != ("PF")/("FR")`
Therefore, EF is not parallel to QR.
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