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प्रश्न
Draw the graph of the following lines: y = x + 2 and 5x + 3y = 30.
Find their point of intersection and the area of triangle formed by the two lines with x-axis.
आलेख
योग
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उत्तर
Given:
y = x + 2
5x + 3y = 30
5x + 3(x + 2) = 30
5x + 3x + 6 = 30
8x = 24
x = 3
y = 3 + 2 = 5
Intersection point = (3, 5)
y = 0 ⇒ x + 2 ⇒ x = −2 ⇒ Point A = (–2, 0)
y = 0 = 5x = 30 = x = 6 ⇒ Point B = (6, 0)
Vertices: A(–2, 0), B(6, 0), C(3, 5)
Base = ∣6 − (–2)∣ = 8
Height = 5
Area = `1/2 xx "base" xx "height"`
Area = `1/2 xx 8 xx 5`
20 square units

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