Advertisements
Advertisements
प्रश्न
Draw an obtuse angled Δ STV. Draw its medians and show the centroid.
Advertisements
उत्तर
Steps of construction:
- Draw an obtuse, angled ∆ STV.
- Draw the perpendicular bisector AB of side TV that intersects side TV at L. L is the mid point of TV.
- Join SL, where SL is median to the side TV.
In the same manner, obtain the mid points M and N of sides SV and ST, respectively. - Join TM and VN.
Hence, ∆ STV is the required triangle in which the medians SL, TM and VN to the sides TV, SV and ST respectively intersect at point G.
The point G is the centroid of ∆ STV.
संबंधित प्रश्न
In ΔPQR, ∠Q = 90°, PQ = 12, QR = 5 and QS is a median. Find l(QS).
In the given figure, point S is any point on side QR of ΔPQR Prove that: PQ + QR + RP > 2PS
Draw an obtuse angled Δ LMN. Draw its altitudes and denote the orthocentre by ‘O’.
The centroid of a triangle divides each medians in the ratio _______
Identify the centroid of ∆PQR
In ∆DEF, DN, EO, FM are medians and point P is the centroid. Find the following
If OE = 36 then EP = ?
If we join a vertex to a point on opposite side which divides that side in the ratio 1 : 1, then what is the special name of that line segment?
What is a median of a triangle?
What is the point where the medians of a triangle meet called?
In a triangle, where is the centroid always located?
