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प्रश्न
Draw a tangent to the circle from the point P having radius 3.6 cm, and centre at O. Point P is at a distance 7.2 cm from the centre.
आकृति
योग
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उत्तर
Radius = 3.6, Distance = 7.2 cm.

Steps of construction:
1. With O as centre, draw a circle of radius 3.6 cm.
2. Draw a line OP = 7.2 cm.
3. Draw a perpendicular bisector of OP which cuts OP at M.
4. With M as centre and MO as radius draw a circle which cuts the previous circle at A and B.
5. Join AP and BP, AP and BP are the required tangents.
Length of the tangents PA = PB = 6.26 cm
Verification: In the right triangle ∆OAP
PA2 = OP2 – OA2
= 7.22 – 3.62
= (7.2 + 3.6) (7.2 – 3.6)
PA2 = 10.8 × 3.6
= `sqrt(38.38)`
PA = 6.2 cm
Length of the tangent = 6.2 cm
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