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प्रश्न
Draw a right angled Δ XYZ. Draw its medians and show their point of concurrence by G.
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उत्तर
Steps of construction:
- Draw a right angled ∆XYZ.
- Draw the perpendicular bisector PQ of side YZ that intersect YZ at L.
- Join XL. XL is the median to the side YZ.
- Draw the perpendicular bisector TU of side ZX that intersect YZ at M.
- Join YM. YM is the median to side ZX.
- Draw the perpendicular bisector RS of side XY that intersect XY at N.
- Join ZN. ZN is the median to the side XY.
Hence, ∆XYZ is the required triangle in which medinas XL, YM and ZN to the sides YZ, ZX and XY respectively, intersect at G.
The point G is the centroid of ∆XYZ..
संबंधित प्रश्न
In ΔPQR, D is the mid-point of `bar(QR)`.
`bar(PM)` is ______.
PD is ______.
Is QM = MR?
Draw rough sketch for the following:
In ΔABC, BE is a median.
Draw rough sketch for the following:
In ΔXYZ, YL is an altitude in the exterior of the triangle.
Draw an acute angled Δ PQR. Draw all of its altitudes. Name the point of concurrence as ‘O’.
Point G is the centroid of ABC.
If l(RG) = 2.5 then l(GC) = ______.
Name the orthocentre of ∆PQR
How many altitudes does a triangle have?
The ______ triangle always has altitude outside itself.
Median is also called ______ in an equilateral triangle.
What do we call the segment from a vertex to the opposite side that forms a 90° angle with that side?
