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प्रश्न
Draw a circle at a radius of 3 cm. Take a point at 5.5 cm from the center at the circle. From point P, draw two tangents to the circle.
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उत्तर

Steps of construction:
(i) Take a point O in the plane paper and draw a circle of radius 3 cm.
(ii) Mark a point P at distance 5.5 cm from the centre O and join OP.
(iii) Draw the right bisector at OP, intersecting OP at Q.
(iv) Taking Q as the centre and OQ = PQ as radius, draw a circle to intersect the given circle at T and T'.
(v) Join PT and PT' to get the required tangent.
Taype (II). Construction of a tangent to a circle from an external point when its centre is known.
Steps of construction:
Let P be the external point from where the tangent are to be drawn to the given circle.
(i) Through P draw a secant PAB to intersect the circle at A and B.

(ii) Join AP to a point C such that AP = DX is equal to the mid-point at AC.
(iii) Draw a semicircle with BC as diameter.
(iv) Draw PD ⊥ BCX intersecting the semicircle at D.
(v) With P as centre and PD as radius draw arcs to intersect the given circle at T and T'.
(vi) Join PT and PT'. Then PT and PT' are the required tangent.
संबंधित प्रश्न
Draw a circle of radius 3 cm. Draw a pair of tangents to this circle, which are inclined to each other at an angle of 60º.
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- What is the point O called?
- OR and OQ are drawn perpendicular to AB and CA respectively. What is the relation between OR and OQ?
- What is the relation between angle ACO and angle BCO?
Construct a triangle ABC in which base BC = 5.5 cm, AB = 6 cm and ∠ABC = 120°.
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- Draw a cyclic quadrilateral ABCD so that D is equidistant from B and C.
Use ruler and compass only for answering this question.
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There is a circle with center O. P is a point from where only one tangent can be drawn to this circle. What can we say about P?
Draw a circle of radius 4 cm. Construct a pair of tangents to it, the angle between which is 60º. Also justify the construction. Measure the distance between the centre of the circle and the point of intersection of tangents.
