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Discuss the trends in chemical reactivity of group 15 elements. - Chemistry

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प्रश्न

Discuss the trends in chemical reactivity of group 15 elements.

विस्तार में उत्तर
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उत्तर १

  1. Reactivity towards hydrogen: The elements of group 15 react with hydrogen to form hydrides of type EH3, where E = N, P, As, Sb, or Bi. The stability of hydrides decreases on moving down from NH3 to BiH3.
  2. Reactivity towards oxygen: The elements of group 15 form two types of oxides, E2O3 and E2O5, where E = N, P, As, Sb, or Bi. The oxide with the element in the higher oxidation state is more acidic than the other. However, the acidic character decreases on moving down a group.
  3. Reactivity towards halogens: The group 15 elements react with halogens to form two series of salts: EX3 and EX5. However, nitrogen does not form NXas it lacks the d-orbital. All trihalides (except NX3) are stable.
  4. Reactivity towards metals: The group 15 elements react with metals to form binary compounds in which metals exhibit −3 oxidation states.
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उत्तर २

  1. Nitrogen is less reactive than other group 15 elements due to the very high bond dissociation enthalpy (941.4 kJ/mol) of the N≡N triple bond.
  2. Phosphorus and other heavier elements have weaker single bonds, so they are more reactive.
  3. Reactivity increases down the group as atomic size increases and ionisation enthalpy decreases.
  4. Nitrogen tends to form N3− ions due to its small size and high electronegativity, while heavier elements are less likely to form such negative ions.
  5. The stability of +3 oxidation state increases down the group due to the inert pair effect, while +5 oxidation state stability decreases.
  6. Group 15 elements form covalent compounds by sharing their three unpaired p-electrons.
  7. Overall, reactivity trends depend on atomic size, bond strength, and oxidation state preferences of the elements.
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अध्याय 7: p-Block Elements - 'NCERT TEXT-BOOK' Exercises [पृष्ठ ४५७]

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नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
अध्याय 7 p-Block Elements
'NCERT TEXT-BOOK' Exercises | Q 7.3 | पृष्ठ ४५७

संबंधित प्रश्न

Nitrogen exists as diatomic molecule and phosphorus as P4. Why?


The oxidation state of nitrogen in dinitrogen trioxide is ____

(a) + 1

(b) + 2

(c) + 3

(d) + 4


Account for the following :

Noble gases have very low boiling points.


Account for the following :

Sulphur in vapour form exhibits paramagnetic behaviour.


[Ar]3d104s24p3 is the electronic configuration of ____________.


In which of the following compound, nitrogen shows the oxidation state of +5?


The tribasic acid is ____________.


Which of the following species has the highest dipole moment?


The correct decreasing order of basic strength is:


The correct order of increasing oxidising power is:


The correct order of oxidising power is:


Acidity of diprotic acid in aqueous solution increases in order.


The oxidation state of central atom in the anion of compound \[\ce{NaH2PO2}\] will be ______.


Which of the following options are not in accordance with the property mentioned against them?

(i) \[\ce{F2 > Cl2 > Br2 > I2}\]  Oxidising power.
(ii) \[\ce{MI > MBr > MC1 > MF}\]   Ionic character of metal halide.
(iii) \[\ce{F2 > Cl2 > Br2 > I2}\]   Bond dissociation enthalpy.
(iv) \[\ce{HI < HBr < HCI < HF}\] Hydrogen-halogen bond strength.

Match the species given in Column I with the shape given in Column II and mark the correct option.

Column I Column II
(A) \[\ce{SF4}\] (1) Tetrahedral
(B) \[\ce{BrF2}\] (2) Pyramidal
(C) \[\ce{BrO^{-}3}\] (3) Sea-saw shaped
(D) \[\ce{NH^{+}4}\] (4) Bent T-shaped

In \[\ce{PCl5}\], phosphorus is in sp3d hybridised state but all its five bonds are not equivalent. Justify your answer with reason.


The electronic configuration of Cu (atomic number 29) is


The elements with zero electron affinity are


In NH3 and PH3 the common is:-


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