Advertisements
Advertisements
प्रश्न
Discuss the nature of the roots of the following quadratic equations : -2x2 + x + 1 = 0
Advertisements
उत्तर
-2x2 + x + 1 = 0
Here a = -2, b = 1, c = 1
∴ D = b2 - 4ac
= (1)2 - 4 x (-2) x 1
= 1 + 8
= 9
∵ D > 0
∴ Roots are real and distinct.
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equation for x :
9x2 − 6b2x − (a4 − b4) = 0
Find the values of k for which the roots are real and equal in each of the following equation:
kx2 + 4x + 1 = 0
Find the values of k for which the roots are real and equal in the following equation:
x2 – 4kx + k = 0
`(2)/x^2 - (5)/x + 2` = 0
Choose the correct answer from the given four options :
If the equation {k + 1)x² – 2(k – 1)x + 1 = 0 has equal roots, then the values of k are
(x2 + 1)2 – x2 = 0 has ______.
State whether the following quadratic equation have two distinct real roots. Justify your answer.
x2 – 3x + 4 = 0
Does there exist a quadratic equation whose coefficients are all distinct irrationals but both the roots are rationals? Why?
Find the roots of the quadratic equation by using the quadratic formula in the following:
–x2 + 7x – 10 = 0
Find the value(s) of 'a' for which the quadratic equation x2 – ax + 1 = 0 has real and equal roots.
