Question

Construct a ΔABC with BC = 7 cm, ∠B = 60° and AB = 6 cm. Construct another triangle whose sides are `3/4` times the corresponding sides of ΔABC

Answer 1

Steps of Construction
Step 1: Draw a line segment BC = 7cm.
Step 2: At B, draw ∠XBC = 60°.
Step 3: With B as center and radius 6 cm, draw an arc cutting the ray BX at A.
Step 4: Join AC. Thus, ΔABC is the required triangle.
Step 5: Below BC, draw an acute angle ∠YBC.
`"Step 6: Along BY, mark four points " B_1 ,B_2 ,B_3  and  B_4  " such  that " BB_1 = B_1 B_2 = B_2 B_3 = B_3 B_4` .

Step 7: Join CB₄ .
Step 8: From B₃ , draw  B₃ C ' ||CB₄  meeting BC at C ' ’.
Step 9: From C’, Draw A'C' || ACmeeting AB in A’.

Here. ΔA'BC ' is the required triangle whose sides are `3/4`times the corresponding sides of  ΔABC.