Question

Consider the following frequency distribution:

Class	0 – 5	6 – 11	12 – 17	18 – 23	24 – 29
Frequency	13	10	15	8	11

The upper limit of the median class is:

विकल्प

• 17

• 17.5

• 18

• 18.5

Answer 1

17.5

Explanation:

According to the question,

Classes are not continuous,

Hence, we make the data continuous by subtracting 0.5 from lower limit and adding 0.5 to upper limit of each class.

Class	Frequency	Cumulative Frequency
0.5 – 5.5	13	13
6.5 – 11.5	10	23
11.5 – 17.5	15	38
17.5 – 23.5	8	46
23.5 – 29.5	11	57

According to the question,

`N/2 = 57/2 = 28.5`

28.5 lies in between the interval 11.5 – 17.5.

Therefore, the upper limit is 17.5