हिंदी

Compare the quadratic equation x2+93x+24=0 to ax2 + bx + c = 0 and find the value of discriminant and hence write the nature of the roots.

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प्रश्न

Compare the quadratic equation `x^2 + 9sqrt(3)x + 24 = 0` to ax2 + bx + c = 0 and find the value of discriminant and hence write the nature of the roots.

योग
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उत्तर

Given equation is, `x^2 + 9sqrt(3)x + 24 = 0`

Comparing the given equation with ax2 + bx + c = 0, we get

a = 1, b = `9sqrt(3)`, c = 24

Discriminant, D = b2 – 4ac

= `(9sqrt(3))^2 - 4(1)(24)`

= 243 – 96

= 147

Here, D > 0.

As a result, the roots of the quadratic equation are both real and unequal.

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