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Check whether the following system of equations is consistent or not. If consistent, solve graphically: x − 2y + 4 = 0, 2x − y − 4 = 0 - Mathematics

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प्रश्न

Check whether the following system of equations is consistent or not. If consistent, solve graphically:

x − 2y + 4 = 0, 2x − y − 4 = 0

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योग
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उत्तर

x − 2y + 4 = 0    ....(i)

2x − y − 4 = 0    ....(ii)

Compare equations (i) and (ii) with a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0.

Then, a1 = 1, b1 = −2, c1 = 4, a2 = 2, b2 = −1, c2 = −4

`(a_1)/(a_2) = 1/2, (b_1)/(b_2) = (-2)/(-1)`

`(a_1)/(a_2) ≠ (b_1)/(b_2)`

∴ Consistent equation.

From equation (i),

x − 2y + 4 = 0

Put x = 0 and y = 0 in equation (i),

y = 2 and x = −4

x 0 −4
y 2 0

From equation (ii)

2x − y − 4 = 0

Put x = 0 and y = 0 in equation (ii),

x 0 2
y −4 0

Equations (i) and (ii) intersect at the point (4, 4).

Hence, the graphical solution of the equations is (4, 4).

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