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प्रश्न
Check whether the following pair of equations is consistent or not. If consistent, solve graphically:
x + 3y = 6
3y − 2x = −12
आलेख
योग
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उत्तर
x + 3y = 6 .....(i)
− 2x + 3y = −12 ....(ii)
Compare equations (i) and (ii) by a1x + b1y = c1 and a2x + b2y = c2
Then a1 = 1, b1 = 3, c1 = 6, a2 = −2, b2 = 3, c2 = −12
Then `a_1/a_2 = 1/(-2), b_1/b_2 = 3/3 = 1`
`a_1/a_2 ≠ b_1/b_2`
So, the given equations are consistent.
From equation (i)
x + 3y = 6
Put x = 0
0 + 3y = 6
y = `6/3`
y = 2
Put x = 6
6 + 3y = 6
3y = 0
y = 0
y = 0
| x | 0 | 6 |
| y | 2 | 0 |
From equation (ii)
− 2x + 3y = −12
Put x = 0
− 2 × 0 + 3y = −12
3y = −12
y = `(-12)/3`
y = −4
Put x = 6
− 2 × 6 + 3y = −12
y = 0
| x | 0 | 6 |
| y | −4 | 0 |

Equations (i) and (ii) intersect each other at point (6, 0)
Hence, the solution of the given equations is (6, 0).
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