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प्रश्न
Calculate the number of unpaired electrons in Ti3+, Mn2+ and calculate the spin only magnetic moment.
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उत्तर
Ti3+:
Ti (Z = 22)
Electronic configuration [Ar] 3d2 4s2
Ti3+ – Electronic configuration [Ar] 3d1
So, the number of unpaired electrons in Ti3+ is equal to 1.
Spin only magnetic moment of Ti3+ = `sqrt(1 (1 + 2)) = sqrt3` = 1.73 µB
Mn2+:
Mn (Z = 25)
Electronic configuration [Ar] 3d5 4s2
Mn2+ – Electronic configuration [Ar] 3d5
Mn2+ has 5 unpaired electrons.
Spin only magnetic moment of Mn2+ = `sqrt(5 (5 + 2)) = sqrt35` = 5.91 µB
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संबंधित प्रश्न
Which one of the following ions has the same number of unpaired electrons as present in V3+?
The magnetic moment of Mn2+ ion is ____________.
What are transition metals? Give four examples.
What are interstitial compounds?
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Explain the variation in `"E"_ ("M"^(3+)//"M"^(2+))^0` 3d series.
Compare the ionization enthalpies of the first series of the transition elements.
Describe the variable oxidation state of 3d series elements.
Why first ionization enthalpy of chromium is lower than that of zinc?
Transition metals show high melting points why?
