Question

Calculate the mass of ammonia that can be obtained from 21.4 g of NH₄Cl by the reaction:

\[\ce{2NH4Cl + Ca(OH)2 -> CaCl2 + 2H2O + 2NH3}\]

Answer 1

Mol. Mass of 2NH₄Cl = 2[14 + (1 × 4) + 35.5] = 2[53.5] = 107 g

107 g NH₄Cl gives = 34 g NH₃

So, 21.4 g NH₄Cl will give = `21.4 × 34/107`

= 6.8 g NH₃