Question

Calculate the degree of hydrolysis of 0.2 (M) sodium acetate solution. 
(Hydrolysis constant of sodium acetate = 5.6 × 10^-10 and ionic product of H₂O = 10^-14 at 25°C).

Answer 1

Degree of hydrolysis    h = `sqrt((K_h)/c)`

Given,                        K_h = 5.6 × 10^-10 

                                    c = 0.2 M 

Hence,                       `h = sqrt((5.6xx10^-10)/0.2) = 5.29 xx 10^-5`