Advertisements
Advertisements
प्रश्न
Calculate the mass of ice required to lower the temperature of 300 g of water 40°C to water at 0°C.
(Specific latent heat of ice = 336 J/g, the Specific heat capacity of water = 4.2J/g°C)
Advertisements
उत्तर
Let m be the mass of the ice to be added.
Heat energy required to melt to lower the temperature is = mL = m x 336
Heat energy imparted by the water in fall of its temperature from 40°C to
0°C = mass of the water x specific heat capacity x fall in temperature
= 300 x 4.2 x 40°C
If there is no loss of heat,
m x 336 J/g = 300 g x 4.2 J/g°C x 40°C
`:. m = (300 xx 4.2 xx 40)/336`
∴ m = 150g
APPEARS IN
संबंधित प्रश्न
State two factors upon which the heat absorbed by a body depends
Give a mathematical relation between Heat Capacity and Specific Heat Capacity.
A calorimeter has mass 100 g and specific heat 0.1 kcal/ kg°C. It contains 250 gm of liquid at 30°C having specific heat of 0.4 kcal/kg°C. If we drop a piece of ice of mass 10 g at 0°C, What will be the temperature of the mixture?
A solid of mass 80 g at 80°C is dropped in 400 g water at 10°C. If final temp. is 30°C, find the sp. heat cap. of the solid.
What is heat? What is the S. I. unit of heat?
The molar specific heats of an ideal gas at constant pressure and constant volume are denoted by Cp and Cv respectively. If `gamma = "C"_"p"/"C"_"v"` and R is the universal gas constant, then Cp is equal to ______.
An office room contains about 4000 moles of air. The change in the internal energy of this much air when it is cooled from 34° C to 19° C at a constant pressure of 1.0 atm is (Use `gamma_"air"` = 1.4 and Universal gas constant = 8.314 J / mol K) ____________.
The specific heat capacity of water is ______.
