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प्रश्न
Calculate:
(ii) ∠ABC

योग
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उत्तर
Given: ACE = 1300; AD = BD = CD
Proof:
(ii)
∠ACD = ∠ABD + ∠DAB [ Exterior angle is equal to sum of opp. interor angle ]
But AD =BD
∴ ∠DAB = ∠ABD
⇒ 800 = ∠ABD + ∠ABD
⇒ 2∠BD = 800
⇒ ∠ABD = 400 = ∠DAB.........(ii)
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