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C(diamond) → C(graphite), ∆H = –ve, this indicates that

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प्रश्न

C(diamond) → C(graphite), ∆H = –ve, this indicates that

विकल्प

  • graphite is more stable than diamond

  • graphite has more energy than diamond

  • both are equally stable

  • stability cannot be predicted

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उत्तर

graphite is more stable than diamond

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Thermodynamics - Evaluation [पृष्ठ २२२]

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सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 7 Thermodynamics
Evaluation | Q I. 10. | पृष्ठ २२२
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