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By the principle of Mathematical induction, prove that, for n ≥ 11.2 + 2.3 + 3.4 + ... + n.(n + 1) = nnnn(n+1)(n+2)3 - Mathematics

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प्रश्न

By the principle of Mathematical induction, prove that, for n ≥ 1
1.2 + 2.3 + 3.4 + ... + n.(n + 1) = `("n"("n" + 1)("n" + 2))/3`

योग
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उत्तर

Let P(n) = 1.2 + 2.3 + 3.4 + ... + n.(n + 1) = `("n"("n" + 1)("n" + 2))/3`

For n = 1

P(1) = 1(1 + 1)

= `((1 + 1)(1 + 2))/3`

⇒ 2 = 2

∴ P(1) is true

Let P(n) b true for n = k

∴ P(k) = 1.2 + 2.3 + 3.4 +... + k(k + 1)

= `[("k"("k" + 1)("k" + 2))/3]`  ......(i)

For n = k + 1

P(k + 1) = 1.2 + 2.3 + 3.4  .... + k(k + 1) + (k + 1)(k + 2)

= `(""("k" + 1)("k" + 2))/3 + ("k" + )("k"+ 2)`  .....[Using (i)]

= `("k" + 1)("k" + )["k"/3 + 1]`

= `("k" + 1)("k" + 2)[(("k" + 3))/3]`

=`(("k" + 1)("k" + 2)("k" + 3))/3`

∴ P(k + 1) is true

Thus P(k) is true

⇒ P(k + 1) is true

Hence by principle of mathematical induction

P(n) is true for all n ∈ N

shaalaa.com
Mathematical Induction
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Combinatorics and Mathematical Induction - Exercise 4.4 [पृष्ठ १९६]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 4 Combinatorics and Mathematical Induction
Exercise 4.4 | Q 4 | पृष्ठ १९६

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