Question

Binding energy per nucleon for helium nucleus (2 He) is 7.0 MeV Find value of mass defect for helium nucleus

Answer 1

BE for `""_2^4"He"0` = 7.0 Me V per nucleon

If Δm is the mass defect, then total BE =  Δm x 931.5 MeV

∴ BE per nucleon = `(Δm xx 931.5)/(4)` MeV

`(Δm xx 931.5)/(4)` = 7.0 MeV

Δm = `( 4 xx 7.0 )/931.5` u 

Δm = 0.030059 u