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Assertion: In ΔABC, M and N are midpoints of sides AB and AC. ∠BMN = 6x and ∠B = 2x. ∴ x = 22.5°. Reason: Co-interior angles of parallel lines are supplementary. - Mathematics

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प्रश्न

Assertion: In ΔABC, M and N are midpoints of sides AB and AC. ∠BMN = 6x and ∠B = 2x. ∴ x = 22.5°.


Reason: Co-interior angles of parallel lines are supplementary.

विकल्प

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true but R is the incorrect reason for A.

  • A is true but R is false

  • A is false but R is true.

MCQ
अभिकथन और तर्क
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उत्तर

Both A and R are true and R is the correct reason for A.

Explanation:

Assertion (A):

In ΔABC, M and N are midpoints of sides AB and AC.

Given:

  • ∠BMN = 6x
  • ∠B = 2x

We are to find:

  • x = 22.5°.

Reason (R):

Co-interior angles of parallel lines are supplementary.

Understanding the Geometry:

  • Since M and N are midpoints of AB and AC, the segment MN is parallel to BC by the Midpoint Theorem.
  • In triangle ABC, consider ∠BMN and ∠B.
  • ∠BMN and ∠B are co-interior angles on the same side of the transversal (segment BM) and between the lines MN || BC.

Using Co-Interior Angles:

  • Co-interior angles formed between two parallel lines and a transversal add up to 180°.

So, ∠BMN + ∠B = 180°

⇒ 6x + 2x = 180°

⇒ 8x = 180°

⇒ x = 22.5°

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Mid-point Theorem - MULTIPLE CHOICE QUESTIONS [पृष्ठ ११५]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
अध्याय 10 Mid-point Theorem
MULTIPLE CHOICE QUESTIONS | Q 18. | पृष्ठ ११५
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