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Assertion (A) If the Volumes of Two Spheres Are in the Ratio 27 : 8, Then Their Surface Areas Are in the Ratio 3 : 2. Reason (R) Volume of a Sphere = 4 3 π R 3 Surface Area of a Sphere = 4πR2 - Mathematics

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प्रश्न

Assertion (A)
If the volumes of two spheres are in the ratio 27 : 8, then their surface areas are in the ratio 3 : 2.

Reason (R)
Volume of a sphere `=4/3pi"R"^3`
Surface area of a sphere = 4πR2


  1. Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).
  2. Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (A).
  3. Assertion (A) is true and Reason (R) is false.
  4. Assertion (A) is false and Reason (R) is true.
योग
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उत्तर

Assertion (A) is false and Reason (R) is true.
Assertion (A):

Let R and r be the radii of the two spheres.

Then, ratio of their volumes `=(4/3pi"R"^3)/(4/3 pi"r"^3)`

Therefore,

`=(4/3pi"R"^3)/(4/3 pi"r"^3) = 27/8`

`⇒ "R"^3/"r"^3 = 27/8`

`=> ("R"/"r")^3 = (3/2)^3`

`=> "R"/"r" = 3/2`

Hence, the ratio of their surface areas`= (4 pi"R"^2)/(4pi"r"^2)`

`="R"^2/"r"^2`

`=("R"/"r")^2`

`=(3/2)^2`

`=9/4`

= 9 : 4

Hence, Assertion (A) is false.

Reason (R): The given statement is true.

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अध्याय 19: Volume and Surface Area of Solids - Multiple Choice Questions [पृष्ठ ९२७]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 19 Volume and Surface Area of Solids
Multiple Choice Questions | Q 79 | पृष्ठ ९२७
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