Advertisements
Advertisements
प्रश्न
Area of the circle obtained in 196 m2 is ______.
विकल्प
196 cm2
212 cm2
616 cm2
644 cm2
Advertisements
उत्तर
Area of the circle obtained in 196 m2 is `bb(underline(616 cm^2))`
Explanation:
We know that, area of circle = πr2
= `22/7 xx 14 xx 14`
= 22 × 14 × 2
= 616 cm2
APPEARS IN
संबंधित प्रश्न
In the given figure, ABCD is rectangle of dimensions 21 cm × 14 cm. A semicircle is drawn with BC as diameter. Find the area and the perimeter of the shaded region in the figure.

Find the area of the quadrilateral ABCD in which AD = 24 cm, ∠BAD 90° and ∠BCD is an equilateral triangle having each side equal to 26 cm. Also, find the perimeter of the quadrilateral.
The adjacent sides of a parallelogram are 32 cm and 24 cm. If the distance between the longer sides is 17.4 cm, find the distance between the shorter sides.
A square of diagonal 8 cm is inscribed in a circle. Find the area of the region lying outside the circle and inside the square.
In the following figure, OABC is a square of side 7 cm. If OAPC is a quadrant of a circle with centre O, then find the area of the shaded region. (Use π = 22/7)

In the following figure, AB and CD are two diameters of a circle perpendicular to each other and OD is the diameter of the smaller circle. If OA = 7 cm, find the area of the shaded region.

A circular park has a path of uniform width around it. The difference between the outer and inner circumferences of the circular path is 132 m. Its width is
In the given figure, O is the centre of the bigger circle, and AC is its diameter. Another circle with AB as diameter is drawn. If AC = 54 cm and BC = 10, find the area of the shaded region.

From a thin metallic piece in the shape of a trapezium ABCD in which AB || CD and ∠BCD = 90°, a quarter circle BFEC is removed. Given, AB = BC = 3.5 cm and DE = 2 cm, calculate the area of remaining (shaded) part of metal sheet.

In the given figure, an equilateral triangle has been inscribed in a circle of radius 4 cm. Find the area of the shaded region.

