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प्रश्न
Answer the following question:
Find the equation of the line through A(−2, 3) and perpendicular to the line through S(1, 2) and T(2, 5)
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उत्तर
Slope of ST = `(5 - 2)/(2 - 1) = 3/1` = 3
Since the required line is perpendicular to ST, the slope of the line is `-1/3` and it is passing through A(–2, 3).
∴ Equation of the line in slope point form is y − y1 = m(x − x1)
∴ The equation of the required line is
y – 3 = `-1/3(x + 2)`
∴ 3(y – 3) = –(x + 2)
∴ 3y – 9 = – x – 2
∴ x + 3y = 7
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