हिंदी

An empty cone of radius 3 cm and height 12 cm is filled with ice-cream such that the lower part of the cone which is (1/6)^th of the volume of the cone is unfilled (empty) but a hemisphere - Mathematics

Advertisements
Advertisements

प्रश्न

An empty cone of radius 3 cm and height 12 cm is filled with ice-cream such that the lower part of the cone which is `(1/6)^"th"` of the volume of the cone is unfilled (empty) but a hemisphere is formed on the top. Find the volume of the ice-cream.

योग
Advertisements

उत्तर

A cone of radius (r) = 3 cm and height (h) = 12 cm

The cone is filled with ice-cream except for `1/6^"th"` of the cone’s volume, which is empty.

Also, a hemisphere with a radius of 3 cm is added on top.

We must find total volume of ice-cream.

Volume of cone = `1/3πr^2h`

= `1/3π xx 3 xx 3 xx 12`

= 36π cm3

Volume of ice-cream in the cone = `5/6 xx 36π cm^3`

= 30π cm3

Volume of ice-cream in the hemispherical = `2/3πr^3`

= `2/3π xx 3 xx 3 xx 3`

= 18π cm3

Total volume of the ice-cream = (30π + 18π)

= 48π

= 150.86 cm3 (approx.)

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2025-2026 (March) Board Sample Paper - Standard
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×