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प्रश्न
An empty cone of radius 3 cm and height 12 cm is filled with ice-cream such that the lower part of the cone which is `(1/6)^"th"` of the volume of the cone is unfilled (empty) but a hemisphere is formed on the top. Find the volume of the ice-cream.
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उत्तर
A cone of radius (r) = 3 cm and height (h) = 12 cm
The cone is filled with ice-cream except for `1/6^"th"` of the cone’s volume, which is empty.
Also, a hemisphere with a radius of 3 cm is added on top.
We must find total volume of ice-cream.
Volume of cone = `1/3πr^2h`
= `1/3π xx 3 xx 3 xx 12`
= 36π cm3
Volume of ice-cream in the cone = `5/6 xx 36π cm^3`
= 30π cm3
Volume of ice-cream in the hemispherical = `2/3πr^3`
= `2/3π xx 3 xx 3 xx 3`
= 18π cm3
Total volume of the ice-cream = (30π + 18π)
= 48π
= 150.86 cm3 (approx.)
