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प्रश्न
An element is placed in 2nd Group and 3rd Period of the Periodic Table, burns in presence of oxygen to form a basic oxide.
- Identify the element
- Write the electronic configuration
- Write the balanced equation when it burns in the presence of air
- Write a balanced equation when this oxide is dissolved in water
- Draw the electron dot structure for the formation of this oxide
संक्षेप में उत्तर
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उत्तर
- The element is magnesium (Mg).
- Electronic configuration of the element is 2, 8, 2.
- When magnesium burns in the air it forms magnesium oxide.
\[\ce{2Mg(s) + O_2(g) -> 2MgO(s)}\] - When magnesium oxide is dissolved in water it forms magnesium hydroxide.
\[\ce{MgO(s) + H2O(l) -> Mg(OH)2(aq)}\] 
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