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प्रश्न
An A.C. generator generating an emf of ε = 300 sin (100 πt) V is connected to a series combination of 16μ F capacitor, 1 H inductor and 100 Ω resistor.
Calculate :
1) An impedance of the circuit at the given frequency.
2) Resonant frequency `f_0`
3)Power factor at the resonant frequency `f_0`.
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उत्तर
`E = 300sin(100pit)`
C = capacitor = `16muF`
L = Inductar = 1H

`E = 300sin(100pit)`
From `E = 300 sin (100pit)`
`omega = 100 pi`
`2pif = 100pi`
`:. f = 50 Hz`
`:. X_C =1/(2pifC) = 1/(2pixx50xx16xx10^(-6))= 1/(5026.5 xx 10^(-6)) = 1.98 xx 10^(-4) xx 10^6`
`:. X_C = 198 Ω`
`X_L = 2pifl = 2pi xx 50 xx 1 = 3.14.1 Ω`
1) Impedence of the circuit (Z
`Z = sqrt(R^2 + (X_L -X_C)^2) `
`= [(100)^2 + (314 - 198 )^2]^("1/2")`
= 153.15 Ω
2) Resonant frequency `(f_0)`
`f_0 = 1/(2pisqrt(LC))`
`= 1/(2pisqrt(1xx16xx10^(-6)))`
= 39.84 Hz
3) at Resonance `X_C = X_L`
`:. Z =R`
`cos phi = R/Z`
`cos phi = R/R`
`cos phi = 1`
`"power factor" (cos phi) = 1`
