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प्रश्न
Add:
−3y2 + 10y − 16; 7y2 + 8
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उत्तर
(−3y2 + 10y − 16) + (7y2 + 8)
= −3y2 + 10y − 16 + 7y2 + 8
= (−3y2 + 7y2) + 10y + (−16 + 8)
= 4y2 + 10y + (−8)
= 4y2 + 10y − 8
संबंधित प्रश्न
Add: -7mn + 5, 12mn + 2, 9mn - 8, -2mn - 3
Add: 5m - 7n, 3n - 4m + 2, 2m - 3mn - 5
Subtract: -m2 + 5mn from 4m2 - 3mn + 8
Subtract: 5a2 - 7ab + 5b2 from 3ab - 2a2 -2b2
Subtract:
2a2 from − 7a2
Subtract:
\[\frac{3}{2}x - \frac{5}{4}y - \frac{7}{2}z \text { from }\frac{2}{3}x + \frac{3}{2}y - \frac{4}{3}z\]
Subtract:
\[x^2 y - \frac{4}{5}x y^2 + \frac{4}{3}xy \text { from } \frac{2}{3} x^2 y + \frac{3}{2}x y^2 - \frac{1}{3}xy\]
Multiply: \[\left( \frac{x}{7} + \frac{x^2}{2} \right)by\left( \frac{2}{5} + \frac{9x}{4} \right)\]
If \[x + \frac{1}{x} = 12,\] find the value of \[x - \frac{1}{x} .\]
On simplification `(3x + 3)/3` = ______.
