हिंदी

ΔABC ~ ΔPQR, A(ΔABC) = 80 sq.cm, A(ΔPQR) = 125 sq.cm, then complete A(ΔABC)A(ΔPQR)=80125=[______][______], hence ABPQ=[______][______] - Geometry Mathematics 2

Advertisements
Advertisements

प्रश्न

ΔABC ~ ΔPQR, A(ΔABC) = 80 sq.cm, A(ΔPQR) = 125 sq.cm, then complete `("A"(Δ"ABC"))/("A"(Δ"PQR")) = 80/125 = (["______"])/(["______"])`, hence `"AB"/"PQ" = (["______"])/(["______"])`

योग
Advertisements

उत्तर

`("A"(Δ"ABC"))/("A"(Δ"PQR")) = 80/125` =  `16/25`  ......(i)[Given]

`("A"(Δ"ABC"))/("A"(Δ"PQR")) = "AB"^2/"PQ"^2`   .....(ii)[Theorem of areas of similar triangles]

∴ `"AB"^2/"PQ"^2 = 16/25`     .....[From (i) and (ii)]

Hence `"AB"/"PQ"` = `4/5`   ......[[Taking square root of both sides]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Similarity - Q.2 (A)
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×