Question

A uniform electric field of 50 NC⁻¹ is set up in a region along +x axis. If the potential at the origin (0, 0) is 220 V, find the potential at a point (4m, 3m).

Answer 1

Given: E = 50 N/C along the +x axis

V(0, 0) = 220 V

Since the field is along the +x-axis, the potential changes mainly along the x-direction, and there is no potential change in the y-direction.

The potential difference is provided by:

V = V₀ − E.d

From (0, 0) to (4m, 3m), the movement in the x-direction is 4 m, so:

V(4, 3) = 220 V − (50 × 4)

= 220 − 200 

= 20 V

Thus, the potential at (4m, 3m) is 20 V.