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प्रश्न
A two digit number is such that its product of its digit is 18. When 63 is subtracted from the number, the digits interchange their places. Find the number.
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उत्तर
Let this two digit number be XY. Then as per the question,
XY = 18 ..... (i)
XY - 63 = YX ..... (ii)
Let this two digit number be 'Xi. Which means X=10x (as it comes in tens digit).
Then as per the question, x x y = 1s ... 1ox+y-63=10y+x
⇒ 9x - 9y - 63 = 0
⇒ x - y - 7 = 0
⇒ Puting x = `18/"y"` in above , we get
⇒ 18 - y2 -7y = 0
⇒ y2 + 7y - 18=0
⇒ y2 + 9y -2y- 18=0
⇒ (y+ 2) (y-9)=0.
As y can't be negative, hence y= 9
⇒ Hence x = `18/9 = 2` (from (i))
⇒ Hence answer is 92
Alternate Answer:
From (i), possible combinations are: 29, 36, 63, 92.
From (ii), it's clear that the number 'Xi is more than 63 as that is the only case when we subtract this number by 63, we get a positive value.
Hence, the number is 92 and when we delete it by 63, we get a number of 29 which is a numbers where the digits are interchanged.
Hence answer is 92.
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