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प्रश्न
A sum of ₹ 20,000 yields ₹ 3328 as compound interest in 2 years. Find the rate of interest.
योग
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उत्तर
Given:
- Principal = ₹ 20000
- Compound interest = ₹ 3328
- Time period, T = 2 years
Compound interest = `P(1 + R/100)^T - 1`, where P is the principal, R is the rate of interest and T is the time period.
∴ `20000[(1 + R/100)^2 - 1] = 3328`
⇒ `(1 + R/100)^2 - 1 = 3328/20000`
⇒ `(1 + R/100)^2 = 3328/20000 + 1`
⇒ `(1 + R/100)^2 = 11664/10000`
⇒ `(1 + R/100)^2 = (108/100)^2`
⇒ `R/100 = 108/100 - 1`
⇒ `R/100 = 8/100`
⇒ `R = 8`
Hence, the required rate of interest is 8%.
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