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प्रश्न
A stationery shop owner bought a scientific calculator for ₹ 750. He had put a battery worth ₹ 100 in it. He had spent ₹ 50 for its outer pouch. He was able to sell it for ₹ 850. Find his profit or loss
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उत्तर
Cost of the scientific calculator = ₹ 750
Cost of its battery = ₹ 100
Cost of outer pouch = ₹ 50
Cost Price of the calculator = ₹ 750 + ₹ 100 + ₹ 50
= ₹ 900
S.P. = ₹ 850
Here S.P. > C.P.
Loss = C.P. – S.P.
= 900 – 850
= ₹ 50
Loss = ₹ 50
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| Column I | Column II |
| (i) 3:5 | (A) ₹ 54 |
| (ii) 2.5 | (B) ₹ 47 |
| (iii) 100% | (C) ₹ 53 |
| (iv) `2/3` | (D) ₹ 160 |
| (v) `6 1/4%` | (E) 60% |
| (vi) 12.5% | (F) 25% |
| (vii) SP when CP = ₹ 50 and loss = 6 % | (G) `1/16` |
| (viii) SP when CP = ₹ 50 and profit = ₹ 4 | (H) 250% |
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| (xii) Amount when principal = ₹ 150, Rate of interest = 6% per annum and period = 1 year |
(L) 0.125 |
| (M) 3 : 2 | |
| (N) ₹ 164 | |
| (O) 3 : 3 |
