Advertisements
Advertisements
प्रश्न
A spherical cannon ball, 28 cm in diameter is melted and recast into a right circular conical mould, the base of which is 35 cm in diameter. Find the height of the cone, correct to one place of decimal.
Advertisements
उत्तर
Let h be the height of conee. Then
`1/3 π (35/2)^2 h = 4/3 π (14)^3` ....(Because the volume of conical mould is the same as that of the spherical cannon ball.)
⇒ h = `( 4 xx 14 xx 14 xx 14 xx 2 xx 2)/( 35 xx 35)`
⇒ h = `896/25`
⇒ h = 35.84 cm.
संबंधित प्रश्न
Find the surface area of a sphere of diameter 21 cm.
`["Assume "pi=22/7]`
A certain number of metallic cones, each of radius 2 cm and height 3 cm are melted and recast into a solid sphere of radius 6 cm. Find the number of cones.
Find the surface area of a sphere of radius 14 cm.
How many balls each of radius 1 cm can be made by melting a bigger ball whose diameter is 8 cm?
If a sphere is inscribed in a cube, then the ratio of the volume of the sphere to the volume of the cube is
If a solid sphere of radius r is melted and cast into the shape of a solid cone of height r, then the radius of the base of the cone is
A solid metallic cylinder has a radius of 2 cm and is 45 cm tall. Find the number of metallic spheres of diameter 6 cm that can be made by recasting this cylinder .
The given figure shows the cross-section of a cone, a cylinder and a hemisphere all with the same diameter 10 cm and the other dimensions are as shown.
Calculate :
- the total surface area.
- the total volume of the solid and
- the density of the material if its total weight is 1.7 kg.
A solid, consisting of a right circular cone standing on a hemisphere, is placed upright, in a right circular cylinder, full of water and touches the bottom. Find the volume of water left in the cylinder, having given that the radius of the cylinder is 3 cm and its height is 6 cm; the radius of the hemisphere is 2 cm and the height of the cone is 4 cm. Give your answer to the nearest cubic centimetre.
The radius of a sphere increases by 25%. Find the percentage increase in its surface area
