Question

Answer the following.

A solid metal sphere of volume 0.31 m³ is dropped in an ocean where water pressure is 2 × 10⁷ N/m². Calculate change in volume of the sphere if the bulk modulus of the metal is 6.1 × 10¹⁰ N/m².

Answer 1

Given: V = 0.31 m³, dP = 2 × 10⁷ N/m², K = 6.1 × 10¹⁰ N/m²

To find: Change in volume (dV)

Formula: K = V × `"dP"/"dV"`

Calculation: From formula,

dV = `("V" xx "dP")/"K"`

∴ dV = `(0.31 xx 2 xx 10^7)/(6.1 xx 10^10) ~~ 10^-4 "m"^3`

The change in volume of the sphere is 10^-4 m³.