Question

A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm³ of iron has approximately 8 g mass. [Use π = 3.14]

Answer 1

rom the figure, it can be observed that

Height (h₁) of larger cylinder = 220 cm

Radius (r₁) of larger cylinder = `24/2` = 12 cm

Height (h₂) of smaller cylinder = 60 cm

Radius (r₂) of smaller cylinder = 8 cm

Total volume of pole  =  volume of larger cylinder + volume of smaller cylinder

`= pir_1^2h_1+pir_2^2h_2`

`=pi(12)^2xx220+pi(8)^2xx60`

`=pi[144xx220+64xx60]`

= `35520xx3.14`

= 111532.8 cm³

Mass of 1 cm³ iron = 8 g

Mass of 111532.8 cm³ iron

= 111532.8 × 8

= 892262.4 g

= 892.262 kg