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A simple pendulum performs S.H.M. of period 4 seconds. How much time after crossing the mean position, will the displacement of the bob be one-third of its amplitude.

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प्रश्न

A simple pendulum performs S.H.M. of period 4 seconds. How much time after crossing the mean position, will the displacement of the bob be one-third of its amplitude.

योग
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उत्तर

Data: T= 4 s, x = A/3

The displacement of a particle starting into SHM from the mean position is x = A sin wt = A sin `(2π)/"T"`t

∴ A sin `(2π)/"T"`t = `"A"/3`

∴ `(2π)/"T"`t = sin-1 0.3333 = 19.47° = `19.47xxπ/180`rad

∴ `2/4`t = `19.47/180`

∴ t = `19.47/90` = 0.2163 s

∴ The displacement of the bob will be one-third of its amplitude 0.2163 s after crossing the mean position.

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अध्याय 5: Oscillations - Exercises [पृष्ठ १३०]

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बालभारती Physics [English] Standard 12 Maharashtra State Board
अध्याय 5 Oscillations
Exercises | Q 13 | पृष्ठ १३०

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