Question

A pair of dice is tossed. The probability of not getting the sum eight is ______.

विकल्प

• `5/36`

• `31/36`

• `5/18`

• `5/9`

Answer 1

A pair of dice is tossed. The probability of not getting the sum eight is `underlinebb(31/36)`.

Explanation:

When two dice are tossed, the total number of possible outcomes is:

S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

So, the total number of outcomes in the sample space is:

6 × 6 = 36

The sum of 8 can occur in the following 5 outcomes:

(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)

∴ Probability of getting a sum of 8 is `5/36`.

Probability of not getting a sum of 8 = `1 - 5/36`

= `(36 - 5)/36`

= `31/36`

∴ Probability of not getting a sum of 8 is `31/36`.