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प्रश्न
A moving body is covering distances which are proportional to square of the time. Then, the acceleration of the body is ____________.
विकल्प
zero
increasing
constant but not zero
decreasing
MCQ
रिक्त स्थान भरें
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उत्तर
A moving body is covering distances which are proportional to square of the time. Then, the acceleration of the body is constant but not zero.
Explanation:
According to question,
`"s" ∝ "t"^2` or s = ct2
where, c = constant.
v = `"ds"/"dt"` = 2ct m/s
and a = `"dv"/"dt"` = 2c m/s2
∴ The body's acceleration is constant, but not zero.
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