Advertisements
Advertisements
प्रश्न
A metal crystallises in a face-centred cubic structure. If the edge length of its unit cell is ‘a’, the closest approach between two atoms in metallic crystal will be ______.
विकल्प
`sqrt 2 a`
`a/sqrt 2`
2a
`2 sqrt 2 a`
Advertisements
उत्तर
A metal crystallises in a face-centred cubic structure. If the edge length of its unit cell is ‘a’, the closest approach between two atoms in metallic crystal will be `bbunderline(a/sqrt 2)`.
Explanation:
In a face-centred cubic (FCC) structure:
Atoms touch each other along the face diagonal of the cube.
Face diagonal = `sqrt 2 a`
Along this diagonal, two atoms touch each other, meaning Closest distance (or closest approach) = `"Face diagonal"/2`
= `(sqrt 2 * a)/2`
= `a/sqrt 2`
∴ The closest approach between two atoms in metallic crystal will be `a/sqrt 2`.
