हिंदी

A metal crystallises in a face-centred cubic structure. If the edge length of its unit cell is ‘a’, the closest approach between two atoms in metallic crystal will be ______. - Chemistry (Theory)

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प्रश्न

A metal crystallises in a face-centred cubic structure. If the edge length of its unit cell is ‘a’, the closest approach between two atoms in metallic crystal will be ______.

विकल्प

  • `sqrt 2 a`

  • `a/sqrt 2`

  • 2a

  • `2 sqrt 2 a`

MCQ
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उत्तर

A metal crystallises in a face-centred cubic structure. If the edge length of its unit cell is ‘a’, the closest approach between two atoms in metallic crystal will be `bbunderline(a/sqrt 2)`.

Explanation:

In a face-centred cubic (FCC) structure:

Atoms touch each other along the face diagonal of the cube.

Face diagonal = `sqrt 2 a`

Along this diagonal, two atoms touch each other, meaning Closest distance (or closest approach) = `"Face diagonal"/2`

= `(sqrt 2 * a)/2`

= `a/sqrt 2`

∴ The closest approach between two atoms in metallic crystal will be `a/sqrt 2`.

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अध्याय 1: Solid State - OBJECTIVE (MULTIPLE CHOICE) TYPE QUESTIONS [पृष्ठ ४७]

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नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
अध्याय 1 Solid State
OBJECTIVE (MULTIPLE CHOICE) TYPE QUESTIONS | Q 50. | पृष्ठ ४७
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