Question

A man is double his son's age. Twenty years ago, he was six times his son's age. Find the present age of the father and the son.

Answer 1

Let the present age of the son be x years.
Then, the man's age = 2x years.
20 years ago, their ages will be (x - 20)years and (2x - 20)years respectively.
Given, Twenty years ago, son was six times his son's age.
As per given conditions,

`((x - 20))/((2x - 20)) = (1)/(6)`
⇒ 6x - 120 = 2x - 20
⇒ 4x = 100
⇒ x = 25 years.
⇒ y = 50 years.
Thus, the present age of the son is 25 years.
Then, the man's age = 50 years.