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प्रश्न
A man has a Recurring Deposit Account in a bank for `3 1/2` years. If the rate of interest is 12% per annum and the man gets Rs. 10,206 on maturity, find the value of monthly instalments.
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उत्तर
Let instalment per month (P) = Rs. y
Number of months (n) = 42
Rate of interest (r) = 12% p.a.
∴ `S.I. = P xx (n(n + 1))/(2 xx 12) xx r/100`
= `y xx (42(42 + 1))/(2 xx 12) xx 12/100`
= `y xx 1806/24 xx 12/100`
= Rs. 9.03y
Maturity value = Rs. (y × 42) + Rs. 9.03y = Rs. 51.03y
Given maturity value = Rs. 10,206
Then Rs. 51.03y = Rs. 10206
`\implies` y = `10206/51.03` = Rs. 200
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संबंधित प्रश्न
Virat opened a Savings Bank account in a bank on 16th April 2010. His pass book shows the following entries:
| Date | Particulars |
Withdrawal (Rs.) |
Deposit (Rs.) | Balance (Rs.) |
| April 16, 2010 | , By cash | - | 2500 | 2500 |
| April 28th | By cheque | - | 3000 | 5500 |
| May 9th | To cheque | 850 | - | 4650 |
| May 15th | By cash | 1600 | 6250 | |
| May 24th | To cash | 1000 | - | 5250 |
| June 4th | To cash | 500 | - | 4750 |
| June 30th | To cheque | - | 2400 | 7150 |
| July 3rd | By cash | - | 1800 | 8950 |
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Deposit (In Rs.) |
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| January 1st, 2006 | B/F | - | - | 1270 |
| January 7th, 2006 | By Cheque | - | 2310 | 3580 |
| March 9th, 2006 | To Self | 2000 | - | 1580 |
| June 26th, 2006 | By Cash | - | 6200 | 7780 |
| June 10th 2006 | To Cheque | 4500 | - | 3280 |
| July 15th, 2006 | By Clearing | - | 2630 | 5910 |
| October 18th, 2006 | To Cheque | 530 | - | 5380 |
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| November 3rd, 2006 | By Cash | - | 1500 | 4190 |
| December 6th, 2006 | To Cheque | 950 | - | 3240 |
| December 23rd, 2006 | By Transfer | - | 2920 | 6260 |
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Fill in the blanks in the table.
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| ...... | 6% | 4 years | 1200 | ...... |
