Question

A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m. Find its volume. The heap is to be covered by canvas to protect it from rain. Find the area of the canvas required.

`["Assume "pi=22/7]`

 

Answer 1

Radius (r) of heap = `(10.5/2) m` = 5.25 m

Height (h) of heap = 3 m

Volume of heap = `1/3pir^2h`

= `(1/3xx22/7xx(5.25)^2xx3)m^3`

= 86.625 m³

Therefore, the volume of the heap of wheat is 86.625 m³.

Area of canvas required = Curved surface area of cone

πrl = `pirsqrt(r^2+h^2)`

= `[22/7xx5.25xxsqrt((5.25)^2+(3)^2)]m^2`

= `(22/7xx5.25xx6.05)m^2`

= 99.825 m²

Therefore, 99.825 m² canvas will be required to protect the heap from rain.