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प्रश्न
A gas of mass 32 gms has a volume of 20 liters at S.T.P. Calculate the gram molecular weight of the gas.
योग
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उत्तर १
Given:
Mass of gas = 32 g
The volume occupied by 32 gms of gas = 20 liters
Number of moles of gas = `"volume of gas"/"molar gas volume" = 20/22.4 = 0.89~~ 0.9`
Number of moles of gas = `"Mass of gas"/"Gram molecular weight of gas"`
The gram molecular weight of gas = `"Mass of gas"/"Number of moles of gas" = 32/0.9 = 35.55 g`
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उत्तर २
The mass of 22.4l of gas at S.T.P. is equal to its gram molecular mass.
20 litres of gas at S.T.P. weighs = 32 gms
∴ litres of gas will weigh = `32/20 xx 22.4`
= 35.84 gms
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Standard Temperature Pressure (S.T.P.)
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