Question

A gas cylinder contains 24 × 10²⁴ molecules of nitrogen gas. If Avogadro's number is 6 × 10²³ and the relative atomic mass of nitrogen is 14, calculate the volume of nitrogen at STP in dm³.

Answer 1

Nitrogen exists as N₂.

As 6 × 10²³ molecules of nitrogen occupies = 22.4 dm³ at STP

1 molecule will occupy a volume of `222.4/(6 xx 10^23)` dm³

24 × 10²⁴ molecules will occupy = `22.4/(6 xx 10^23) xx 24 xx 10^24`

= 895.9 dm³